en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-27sin(3x)-27xcos(3x))^'

Solution

(- 27 sin (3 x) - 27 x cos (3 x))^{^{'}}

Solution

- 108 cos (3 x) + 81 x sin (3 x)

Solution steps

(- 27 sin (3 x) - 27 x cos (3 x))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - (27 sin (3 x))^{^{'}} - (27 x cos (3 x))^{^{'}}

(27 sin (3 x))^{'} = 81 cos (3 x)

(27 x cos (3 x))^{'} = 27 (cos (3 x) - 3 x sin (3 x))

= - 81 cos (3 x) - 27 (cos (3 x) - 3 x sin (3 x))

Simplify

- 81 cos (3 x) - 27 (cos (3 x) - 3 x sin (3 x)) : - 108 cos (3 x) + 81 x sin (3 x)

= - 108 cos (3 x) + 81 x sin (3 x)

Popular Examples

tangent of f(x)=(2x)/(x^2+1),\at x=-1,-1 tangent of

f (x) = \frac{2 x}{x ^{2} + 1}, at x = - 1, - 1

inverse oflaplace (2e^{-s})/((s+1/5))inverse laplace

\frac{2 e ^{- s}}{( s + \frac{1}{5} )}

y^{''}-5y^'-14y=0

y^{^{''}} - 5 y^{^{'}} - 14 y = 0

(\partial)/(\partial x)(6)

\frac{\partial}{\partial x} (6)

(\partial)/(\partial y)(3x^2e^y)

\frac{\partial}{\partial y} (3 x^{2} e^{y})

Frequently Asked Questions (FAQ)

What is the (-27sin(3x)-27xcos(3x))^' ?
The (-27sin(3x)-27xcos(3x))^' is -108cos(3x)+81xsin(3x)
What is the first (-27sin(3x)-27xcos(3x))^' ?
The first (-27sin(3x)-27xcos(3x))^' is -108cos(3x)+81xsin(3x)