What is (\partial)/(\partial x)(y^4-4xy) ?

The answer to (\partial)/(\partial x)(y^4-4xy) is -4y

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(\partial)/(\partial x)(y^4-4xy)

\frac{\partial}{\partial x} (y^{4} - 4 x y)

- 4 y

Solution steps

\frac{\partial}{\partial x} (y^{4} - 4 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{4}) - \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (y^{4}) = 0

\frac{\partial}{\partial x} (4 x y) = 4 y

= 0 - 4 y

Simplify

= - 4 y

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What is (\partial)/(\partial x)(y^4-4xy) ?
The answer to (\partial)/(\partial x)(y^4-4xy) is -4y