What is laplacetransform sin(9t) ?

The answer to laplacetransform sin(9t) is 9/(s^2+81)

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laplacetransform sin(9t)

laplace transform

sin (9 t)

\frac{9}{s ^{2} + 81}

Solution steps

L {sin (9 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (9 t)} = \frac{9}{s ^{2} + 9 ^{2}}

= \frac{9}{s ^{2} + 9 ^{2}}

= \frac{9}{s ^{2} + 81}

\int \frac{6 x ^{2}}{x ^{3} - 5} d x

\frac{d}{d x} (2 x - y)

\frac{d}{d x} (5 x^{2} \cdot 2 e^{3 x})

\frac{e ^{- s}}{( s + 1 )}

\int sin (t - x) d x

What is laplacetransform sin(9t) ?
The answer to laplacetransform sin(9t) is 9/(s^2+81)