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Popular >

integral from 0 to 1 of (2x^2+1)

Solution

\int_{0}^{1} (2 x^{2} + 1) d x

Solution

\frac{5}{3}

+1

Decimal Notation

1.66666 \dots

Solution steps

\int_{0}^{1} 2 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 x^{2} d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 2 x^{2} d x = \frac{2}{3}

\int_{0}^{1} 1 d x = 1

= \frac{2}{3} + 1

Simplify

\frac{2}{3} + 1 : \frac{5}{3}

= \frac{5}{3}

Popular Examples

f(x)=(7-x^3)^{2/3}

f (x) = (7 - x^{3})^{\frac{2}{3}}

y^{^{'}} - y = 2 x - 3

area sqrt(x),x-6,x,2 area

x, x - 6, x, 2

derivative of xsqrt(x^2+1)derivative of

x x^{2} + 1

derivative of (pi-x^2)

\frac{d}{d x} ((π - x)^{2})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (2x^2+1) ?
The integral from 0 to 1 of (2x^2+1) is 5/3