What is the sum from n=1 to infinity of 6/(n^5) ?

The sum from n=1 to infinity of 6/(n^5) is converges

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sum from n=1 to infinity of 6/(n^5)

n = 1 \sum \infty \frac{6}{n ^{5}}

converges

Solution steps

n = 1 \sum \infty \frac{6}{n ^{5}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 6 \cdot n = 1 \sum \infty \frac{1}{n ^{5}}

Apply p-Series Test:

converges

= 6 converges

= converges

\frac{d}{d x} (- x^{3} + 5 a x^{2} - 3 a^{2} x - b)

f (x) = e^{x - 2}

x^{2} 36 - x^{2}

x^{2} d y - 2 x y d x = x^{4} cos (2 x) d x

\int \frac{2 x ^{2} + 7 x - 3}{x - 2} d x

What is the sum from n=1 to infinity of 6/(n^5) ?
The sum from n=1 to infinity of 6/(n^5) is converges