What is the solution for q^'+q/(20+t)=1 ?

The solution for q^'+q/(20+t)=1 is q(t)=(20t)/(20+t)+(t^2)/(2(20+t))+(c_{1})/(20+t)

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q^'+q/(20+t)=1

q^{^{'}} + \frac{q}{20 + t} = 1

q (t) = \frac{20 t}{20 + t} + \frac{t ^{2}}{2 ( 20 + t )} + \frac{c _{1}}{20 + t}

Solution steps

q^{'} (t) + \frac{q ( t )}{20 + t} = 1

Solve linear ODE:

q (t) = \frac{20 t}{20 + t} + \frac{t ^{2}}{2 ( 20 + t )} + \frac{c _{1}}{20 + t}

q (t) = \frac{20 t}{20 + t} + \frac{t ^{2}}{2 ( 20 + t )} + \frac{c _{1}}{20 + t}

y^{^{'}} = x^{2} \frac{1}{y}

y = x^{2 x}

\frac{d}{d x} (2 + 2 cos (x))

y = - x^{3} + 2, y = x - 3, x = - 1, x = 1

\int \frac{x}{y} d y

What is the solution for q^'+q/(20+t)=1 ?
The solution for q^'+q/(20+t)=1 is q(t)=(20t)/(20+t)+(t^2)/(2(20+t))+(c_{1})/(20+t)