What is the limit as x approaches-1 of sqrt(x+1) ?

The limit as x approaches-1 of sqrt(x+1) is 0

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limit as x approaches-1 of sqrt(x+1)

x \to - 1 lim (x + 1)

0

Solution steps

x \to - 1 lim (x + 1)

Plug in the value

x = - 1

= - 1 + 1

Simplify

= 0

x \to - 3 lim (\frac{2}{( x + 3 ) ^{6}})

y^{^{'}} = (x + y - 3)^{2}, y (0) = 0

\frac{d}{d x} (8 (e^{x} cos (x) - e^{x} sin (x)))

\int \frac{x ^{4} - 5 x ^{3} + 5 x ^{2} + 8}{x ^{3} + 3 x ^{2}} d x

f (x) = 5 x^{2} (x^{3} + 2)

What is the limit as x approaches-1 of sqrt(x+1) ?
The limit as x approaches-1 of sqrt(x+1) is 0