What is the derivative of 5-2sin(x-e^x) ?

The derivative of 5-2sin(x-e^x) is -e^x-2cos(x)

What is the first derivative of 5-2sin(x-e^x) ?

The first derivative of 5-2sin(x-e^x) is -e^x-2cos(x)

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\frac{d}{d x} (5 - 2 sin (x) - e^{x})

- e^{x} - 2 cos (x)

Solution steps

\frac{d}{d x} (5 - 2 sin (x) - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) - \frac{d}{d x} (2 sin (x)) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (5) = 0

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (e^{x}) = e^{x}

= 0 - 2 cos (x) - e^{x}

Simplify

= - e^{x} - 2 cos (x)

\int \frac{t}{( 3 t ^{2} + 1 ) ^{4}} d t

y^{^{'}} + y = cos (t), y (0) = 1

y = lo g_{e} (lo g_{e} (x))

h \to 0 lim (\frac{( h + 2 ) ^{3} - 8}{h})

\int \frac{1}{y} d y

What is the derivative of 5-2sin(x-e^x) ?
The derivative of 5-2sin(x-e^x) is -e^x-2cos(x)
What is the first derivative of 5-2sin(x-e^x) ?
The first derivative of 5-2sin(x-e^x) is -e^x-2cos(x)