What is (\partial)/(\partial x)(sin(8x-9y)) ?

The answer to (\partial)/(\partial x)(sin(8x-9y)) is cos(8x-9y)*8

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(\partial)/(\partial x)(sin(8x-9y))

\frac{\partial}{\partial x} (sin (8 x - 9 y))

cos (8 x - 9 y) \cdot 8

Solution steps

\frac{\partial}{\partial x} (sin (8 x - 9 y))

Treat

y

as a constant

Apply the chain rule:

cos (8 x - 9 y) \frac{\partial}{\partial x} (8 x - 9 y)

= cos (8 x - 9 y) \frac{\partial}{\partial x} (8 x - 9 y)

\frac{\partial}{\partial x} (8 x - 9 y) = 8

= cos (8 x - 9 y) \cdot 8

\frac{x}{2} + 3

\frac{\partial}{\partial x} (ln (x + 2 y + 6 z))

\frac{d}{d x} (A e^{- \frac{3}{2} x} + B e^{3 x} + C x e^{3 x} + d x^{2} e^{3 x})

\frac{d}{d x} ((x^{2} + 4 x - 5)^{4})

\int x^{2} cos (\frac{x}{2}) d x

What is (\partial)/(\partial x)(sin(8x-9y)) ?
The answer to (\partial)/(\partial x)(sin(8x-9y)) is cos(8x-9y)*8