What is the derivative of tan(xe^x) ?

The derivative of tan(xe^x) is sec^2(xe^x)(e^x+e^xx)

What is the first derivative of tan(xe^x) ?

The first derivative of tan(xe^x) is sec^2(xe^x)(e^x+e^xx)

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derivative of

tan (x e^{x})

sec^{2} (x e^{x}) (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (tan (x e^{x}))

Apply the chain rule:

sec^{2} (x e^{x}) \frac{d}{d x} (x e^{x})

= sec^{2} (x e^{x}) \frac{d}{d x} (x e^{x})

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

= sec^{2} (x e^{x}) (e^{x} + e^{x} x)

x \to 0 lim (x^{2} + 5 x)

f (x) = x^{2} + 6 x + 1

y = (x^{2} + e^{x}) x

\frac{d}{d y} (x sin (y))

x \to \infty lim (\frac{5}{4})

What is the derivative of tan(xe^x) ?
The derivative of tan(xe^x) is sec^2(xe^x)(e^x+e^xx)
What is the first derivative of tan(xe^x) ?
The first derivative of tan(xe^x) is sec^2(xe^x)(e^x+e^xx)