What is the solution for (x+y)*y^'=2*x+2*y-3 ?

The solution for (x+y)*y^'=2*x+2*y-3 is y=\W(1/(3e^{-3x+1-c_{1)}})+1-x

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(x+y)y^'=2x+2*y-3

(x + y) \cdot y^{^{'}} = 2 \cdot x + 2 \cdot y - 3

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

Solution steps

(x + y) \cdot y^{'} (x) = 2 \cdot x + 2 \cdot y - 3

Solve using substitution:

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

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What is the solution for (x+y)*y^'=2*x+2*y-3 ?
The solution for (x+y)*y^'=2*x+2*y-3 is y=\W(1/(3e^{-3x+1-c_{1)}})+1-x