What is the derivative of-7/(1+x^2) ?

The derivative of-7/(1+x^2) is (14x)/((1+x^2)^2)

What is the first derivative of-7/(1+x^2) ?

The first derivative of-7/(1+x^2) is (14x)/((1+x^2)^2)

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derivative of

- \frac{7}{1 + x ^{2}}

\frac{14 x}{( 1 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (- \frac{7}{1 + x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 7 \frac{d}{d x} (\frac{1}{1 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 7 \frac{d}{d x} ((1 + x^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + x ^{2} ) ^{2}} \frac{d}{d x} (1 + x^{2})

= - \frac{1}{( 1 + x ^{2} ) ^{2}} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= - 7 (- \frac{1}{( 1 + x ^{2} ) ^{2}} \cdot 2 x)

Simplify

- 7 (- \frac{1}{( 1 + x ^{2} ) ^{2}} \cdot 2 x) : \frac{14 x}{( 1 + x ^{2} ) ^{2}}

= \frac{14 x}{( 1 + x ^{2} ) ^{2}}

n = 1 \sum \infty \frac{n}{2 n ^{3} + 3}

\frac{4 x + 5}{4 x - 5}

\frac{1}{( s ^{2} )}

\int \frac{1}{x ^{2} - 4 x + 20} d x

f (x) = x^{2} sin (\frac{1}{x})

What is the derivative of-7/(1+x^2) ?
The derivative of-7/(1+x^2) is (14x)/((1+x^2)^2)
What is the first derivative of-7/(1+x^2) ?
The first derivative of-7/(1+x^2) is (14x)/((1+x^2)^2)