What is the solution for (14-12y+e-3x)dx-4dy=0 ?

The solution for (14-12y+e-3x)dx-4dy=0 is y=-x/4+(e+15)/(12)+(c_{1})/(e^{3x)}

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(14-12y+e-3x)dx-4dy=0

(14 - 12 y + e - 3 x) d x - 4 d y = 0

y = - \frac{x}{4} + \frac{e + 15}{12} + \frac{c _{1}}{e ^{3 x}}

Solution steps

(14 - 12 y + e - 3 x) d x - 4 d y = 0

Solve linear ODE:

y = - \frac{x}{4} + \frac{e + 15}{12} + \frac{c _{1}}{e ^{3 x}}

y = - \frac{x}{4} + \frac{e + 15}{12} + \frac{c _{1}}{e ^{3 x}}

n = 1 \sum \infty \frac{e ^{\frac{1}{n}}}{n}

\frac{1}{( s + 2 ) ^{2} + 4}

\int \frac{3 x - 4}{x ^{2} - x - 2} d x

\int \frac{5 x ^{2} + 9 x + 5}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d a} (sin (a) - sin (2 a) + sin (3 a))

What is the solution for (14-12y+e-3x)dx-4dy=0 ?
The solution for (14-12y+e-3x)dx-4dy=0 is y=-x/4+(e+15)/(12)+(c_{1})/(e^{3x)}