What is the limit as x approaches 1 of ln(8x)+e^x ?

The limit as x approaches 1 of ln(8x)+e^x is 3ln(2)+e

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limit as x approaches 1 of ln(8x)+e^x

x \to 1 lim (ln (8 x) + e^{x})

3 ln (2) + e

Decimal Notation

4.79772 \dots

Solution steps

x \to 1 lim (ln (8 x) + e^{x})

Plug in the value

x = 1

= ln (8 \cdot 1) + e^{1}

Simplify

ln (8 \cdot 1) + e^{1} : 3 ln (2) + e

= 3 ln (2) + e

\frac{d}{d x} (5 e^{- 0.5 x} + 100)

\int \frac{2 ^{18 x}}{4} d x

y = 4 - x^{2}, y = 16 - 7 x

(x^{2} + 4) \frac{d y}{d x} = 2 x - 8 x y

x \to 2 lim (r (x))

What is the limit as x approaches 1 of ln(8x)+e^x ?
The limit as x approaches 1 of ln(8x)+e^x is 3ln(2)+e