What is the derivative of x^2+2x-3 ?

The derivative of x^2+2x-3 is 2x+2

What is the first derivative of x^2+2x-3 ?

The first derivative of x^2+2x-3 is 2x+2

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\frac{d}{d x} (x^{2} + 2 x - 3)

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

\frac{\partial}{\partial y} (\frac{x ^{2}}{1 + y ^{3}})

\frac{d}{d x} (a x e^{b x^{2}})

\int - \frac{arccot ( x )}{1 + x ^{2}} d x

\frac{\partial}{\partial x} (3 x^{2} + 6 x y)

\frac{d}{d x} (\frac{12 ( 3 x ^{3} - 16 )}{4 x - x ^{4}})

What is the derivative of x^2+2x-3 ?
The derivative of x^2+2x-3 is 2x+2
What is the first derivative of x^2+2x-3 ?
The first derivative of x^2+2x-3 is 2x+2