What is the derivative of x^4+y^4 ?

The derivative of x^4+y^4 is 4x^3+4y^3(dy)/(dx)

What is the first derivative of x^4+y^4 ?

The first derivative of x^4+y^4 is 4x^3+4y^3(dy)/(dx)

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\frac{d}{d x} (x^{4} + y^{4})

4 x^{3} + 4 y^{3} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{4} + y^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (y^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (y^{4}) = 4 y^{3} \frac{d y}{d x}

= 4 x^{3} + 4 y^{3} \frac{d y}{d x}

\frac{d}{d x} (\frac{x}{x ^{3} + 1})

f (x) = cos^{2} (2 x)

\frac{1 - 2 x}{1 + 2 x}

\frac{d}{d x} (3^{x} - 2)

\frac{d}{d x} (e^{x^{2}} y)

What is the derivative of x^4+y^4 ?
The derivative of x^4+y^4 is 4x^3+4y^3(dy)/(dx)
What is the first derivative of x^4+y^4 ?
The first derivative of x^4+y^4 is 4x^3+4y^3(dy)/(dx)