What is the derivative of 2x^2-3x+2 ?

The derivative of 2x^2-3x+2 is 4x-3

What is the first derivative of 2x^2-3x+2 ?

The first derivative of 2x^2-3x+2 is 4x-3

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\frac{d}{d x} (2 x^{2} - 3 x + 2)

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 4 x - 3 + 0

Simplify

= 4 x - 3

\int \frac{1}{3} x^{2} d x

x \to 0 lim (x^{3} + x)

\int \frac{2}{( x ^{2} + 1 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (\frac{1 - 3 x}{2 x + 1})

x \to \frac{π}{6} lim (sin (x))

What is the derivative of 2x^2-3x+2 ?
The derivative of 2x^2-3x+2 is 4x-3
What is the first derivative of 2x^2-3x+2 ?
The first derivative of 2x^2-3x+2 is 4x-3