What is the tangent of y=8sqrt(x),(4,16) ?

The tangent of y=8sqrt(x),(4,16) is y=2x+8

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tangent of y=8sqrt(x),(4,16)

tangent of

y = 8 x, (4, 16)

y = 2 x + 8

Solution steps

Find the slope of

y = 8 x : \frac{d y}{d x} = \frac{4}{x}

Compute the slope of

y = 8 x

(4, 16) : m = 2

Find the line with slope m=

2

and passing through

(4, 16) : y = 2 x + 8

y = 2 x + 8

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x - 3

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What is the tangent of y=8sqrt(x),(4,16) ?
The tangent of y=8sqrt(x),(4,16) is y=2x+8