What is the solution for (dy}{dx}=\frac{1-y^2)/x ?

The solution for (dy}{dx}=\frac{1-y^2)/x is y=-(e^{2c_{1}}x^2)/(1-e^{2c_{1)}x^2}-1/(1-e^{2c_{1)}x^2}

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(dy}{dx}=\frac{1-y^2)/x

\frac{d y}{d x} = \frac{1 - y ^{2}}{x}

y = - \frac{e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}} - \frac{1}{1 - e ^{2 c_{1}} x ^{2}}

Solution steps

\frac{d y}{d x} = \frac{1 - y ^{2}}{x}

Solve separable ODE:

y = - \frac{e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}} - \frac{1}{1 - e ^{2 c_{1}} x ^{2}}

y = - \frac{e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}} - \frac{1}{1 - e ^{2 c_{1}} x ^{2}}

n = 6 \sum \infty \frac{5 ^{n}}{1 0 ^{n}}

\int \frac{tan ^{3} ( \frac{2}{z} )}{z ^{2}}

\frac{d y}{d x} + x y = y^{4}

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What is the solution for (dy}{dx}=\frac{1-y^2)/x ?
The solution for (dy}{dx}=\frac{1-y^2)/x is y=-(e^{2c_{1}}x^2)/(1-e^{2c_{1)}x^2}-1/(1-e^{2c_{1)}x^2}