What is the derivative of 5/(8t) ?

The derivative of 5/(8t) is -5/(8t^2)

What is the first derivative of 5/(8t) ?

The first derivative of 5/(8t) is -5/(8t^2)

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derivative of

\frac{5}{8 t}

- \frac{5}{8 t ^{2}}

Solution steps

\frac{d}{d t} (\frac{5}{8 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{5}{8} \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{5}{8} \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{5}{8} (- 1 \cdot t^{- 1 - 1})

Simplify

\frac{5}{8} (- 1 \cdot t^{- 1 - 1}) : - \frac{5}{8 t ^{2}}

= - \frac{5}{8 t ^{2}}

\frac{\partial}{\partial y} (x^{2} y^{3} z)

y = - 3 x + 5

k = 1 \sum \infty 3^{k} 7

\frac{d y}{d x} = 4 y + x^{2} + 7

\frac{\partial}{\partial y} (x^{2} + y^{2})

What is the derivative of 5/(8t) ?
The derivative of 5/(8t) is -5/(8t^2)
What is the first derivative of 5/(8t) ?
The first derivative of 5/(8t) is -5/(8t^2)