What is the limit as x approaches 1 of ln(3x)+e^x ?

The limit as x approaches 1 of ln(3x)+e^x is ln(3)+e

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limit as x approaches 1 of ln(3x)+e^x

x \to 1 lim (ln (3 x) + e^{x})

ln (3) + e

Decimal Notation

3.81689 \dots

Solution steps

x \to 1 lim (ln (3 x) + e^{x})

Plug in the value

x = 1

= ln (3 \cdot 1) + e^{1}

Simplify

= ln (3) + e

x \to 2 lim (2 x^{2} + 4 x + a)

\int \frac{x}{16 x ^{4} - 1} d x

\frac{3 ( 7 - x ) + 5 9 + x ^{2}}{15}

What is the limit as x approaches 1 of ln(3x)+e^x ?
The limit as x approaches 1 of ln(3x)+e^x is ln(3)+e