What is the derivative of x^2tan(1/x) ?

The derivative of x^2tan(1/x) is 2xtan(1/x)-sec^2(1/x)

What is the first derivative of x^2tan(1/x) ?

The first derivative of x^2tan(1/x) is 2xtan(1/x)-sec^2(1/x)

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\frac{d}{d x} (x^{2} tan (\frac{1}{x}))

2 x tan (\frac{1}{x}) - sec^{2} (\frac{1}{x})

Solution steps

\frac{d}{d x} (x^{2} tan (\frac{1}{x}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = tan (\frac{1}{x})

= \frac{d}{d x} (x^{2}) tan (\frac{1}{x}) + \frac{d}{d x} (tan (\frac{1}{x})) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (tan (\frac{1}{x})) = - \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}

= 2 x tan (\frac{1}{x}) + (- \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}) x^{2}

Simplify

2 x tan (\frac{1}{x}) + (- \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}) x^{2} : 2 x tan (\frac{1}{x}) - sec^{2} (\frac{1}{x})

= 2 x tan (\frac{1}{x}) - sec^{2} (\frac{1}{x})

\frac{x ^{2} - 2}{2 x + 1}

\int (\frac{1}{x ^{2} - 4}) d x

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} + x})

f (x) = 4 + 3 x

\frac{d}{d x} (9^{4 x})

What is the derivative of x^2tan(1/x) ?
The derivative of x^2tan(1/x) is 2xtan(1/x)-sec^2(1/x)
What is the first derivative of x^2tan(1/x) ?
The first derivative of x^2tan(1/x) is 2xtan(1/x)-sec^2(1/x)