What is the solution for x^2(dy)/(dx)+y^2-xy=0 ?

The solution for x^2(dy)/(dx)+y^2-xy=0 is y= x/(ln(x)+c_{1)}

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x^2(dy)/(dx)+y^2-xy=0

x^{2} \frac{d y}{d x} + y^{2} - x y = 0

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

x^{2} \frac{d y}{d x} + y^{2} - x y = 0

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

arcsec (9 x)

\int \frac{6}{x ln ^{3} ( x )} d x

\frac{\partial}{\partial y} (ln (x^{5} + y^{5}))

\int \frac{8 + 4 x}{1 + x ^{2}} d x

f^{^{'}} (x) = 3.52 x^{2} - 30.1 x + 81

What is the solution for x^2(dy)/(dx)+y^2-xy=0 ?
The solution for x^2(dy)/(dx)+y^2-xy=0 is y= x/(ln(x)+c_{1)}