What is the tangent of f(x)= 6/x ,\at x=4 ?

The tangent of f(x)= 6/x ,\at x=4 is y=-3/8 x+3

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tangent of f(x)= 6/x ,\at x=4

tangent of

f (x) = \frac{6}{x}, at x = 4

y = - \frac{3}{8} x + 3

Solution steps

Find the tangent point:

(4, \frac{3}{2})

Find the slope of

f (x) = \frac{6}{x} : \frac{df ( x )}{d x} = - \frac{6}{x ^{2}}

Compute the slope of

f (x) = \frac{6}{x}

x = 4 : m = - \frac{3}{8}

Find the line with slope m=

- \frac{3}{8}

and passing through

(4, \frac{3}{2}) : y = - \frac{3}{8} x + 3

y = - \frac{3}{8} x + 3

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\int \frac{x}{1000} x^{2} + 2500 d x

\frac{d}{d x} ((x - 5) \cdot ln (\frac{x}{5}))

\frac{d}{d x} (- \frac{375}{x ^{4}})

\int_{- 2}^{3} x^{2} - x - 6 d x

What is the tangent of f(x)= 6/x ,\at x=4 ?
The tangent of f(x)= 6/x ,\at x=4 is y=-3/8 x+3