What is the integral of (tan(x))/1 ?

The integral of (tan(x))/1 is -ln|cos(x)|+C

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integral of (tan(x))/1

\int \frac{tan ( x )}{1} d x

- ln ∣ cos (x) ∣ + C

Solution steps

\int \frac{tan ( x )}{1} d x

Rewrite using trig identities

= \int \frac{sin ( x )}{cos ( x )} d x

Apply u-substitution

: \int - \frac{1}{u} d u

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = cos (x)

= - ln ∣ cos (x) ∣

Add a constant to the solution

= - ln ∣ cos (x) ∣ + C

y^{^{'}} = t - 2 y

\int_{2}^{\infty} \frac{1}{x ^{4}} d x

f (x) = x^{2} - 7 x + 12, at x = 2

y = 4 - 4 + x

\frac{d}{d r ( t )} (\frac{s - r ( t )}{t})

What is the integral of (tan(x))/1 ?
The integral of (tan(x))/1 is -ln|cos(x)|+C