What is the solution for x*y^'+y=x^4*y^3 ?

The solution for x*y^'+y=x^4*y^3 is y= 1/(xsqrt(-x^2+c_{1))},y=-1/(xsqrt(-x^2+c_{1))}

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xy^'+y=x^4y^3

x \cdot y^{^{'}} + y = x^{4} \cdot y^{3}

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

Solution steps

x \cdot y^{'} (x) + y = x^{4} \cdot y^{3}

Solve Bernoulli ODE:

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

y = \frac{1}{x - x ^{2} + c _{1}}, y = - \frac{1}{x - x ^{2} + c _{1}}

\int t^{19} e^{- t^{20}} d t

\frac{5}{s ^{3} - 2 s ^{2} - 3 s}

(2005, 56), (2010, 59)

\int_{0}^{1} \frac{3}{x ^{2} - x - 2} d x

\frac{3}{x ^{2}}

What is the solution for x*y^'+y=x^4*y^3 ?
The solution for x*y^'+y=x^4*y^3 is y= 1/(xsqrt(-x^2+c_{1))},y=-1/(xsqrt(-x^2+c_{1))}