What is the sum from n=1 to infinity of (-1)^ne^{-n} ?

The sum from n=1 to infinity of (-1)^ne^{-n} is converges

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sum from n=1 to infinity of (-1)^ne^{-n}

n = 1 \sum \infty (- 1)^{n} e^{- n}

converges

Solution steps

n = 1 \sum \infty (- 1)^{n} e^{- n}

Apply Alternating Series Test:

converges

= converges

x \to 2 lim (3 x - 9)

\frac{d}{d x} (- 125 cos (5 x))

\int_{\frac{1}{2}}^{\frac{3}{4}} \frac{1}{u ^{2}} d u

\int_{- 1}^{3} 3 x^{2} + 4 x d x

y = arcsec (x^{2} + 1)

What is the sum from n=1 to infinity of (-1)^ne^{-n} ?
The sum from n=1 to infinity of (-1)^ne^{-n} is converges