What is the d/(dt)(7cos(t)) ?

The d/(dt)(7cos(t)) is -7sin(t)

What is the first d/(dt)(7cos(t)) ?

The first d/(dt)(7cos(t)) is -7sin(t)

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\frac{d}{d t} (7 cos (t))

- 7 sin (t)

Solution steps

\frac{d}{d t} (7 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 7 (- sin (t))

Simplify

= - 7 sin (t)

y = ln (1 + sin (x))

\int \frac{sin ( x )}{7 + cos ^{2} ( x )} d x

\frac{d}{d x} (4 x^{4} - 32 x^{3} + 89 x^{2} - 95 x + 29)

x \to - 5 + lim (\frac{x + 4}{x + 5})

\int_{0}^{2} 4 x - 2 x^{2} d x