What is (\partial)/(\partial x)(e^{-7y}sin(7x)) ?

The answer to (\partial)/(\partial x)(e^{-7y}sin(7x)) is e^{-7y}cos(7x)*7

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(\partial)/(\partial x)(e^{-7y}sin(7x))

\frac{\partial}{\partial x} (e^{- 7 y} sin (7 x))

e^{- 7 y} cos (7 x) \cdot 7

Solution steps

\frac{\partial}{\partial x} (e^{- 7 y} sin (7 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 7 y} \frac{\partial}{\partial x} (sin (7 x))

Apply the chain rule:

cos (7 x) \frac{\partial}{\partial x} (7 x)

= cos (7 x) \frac{\partial}{\partial x} (7 x)

\frac{\partial}{\partial x} (7 x) = 7

= e^{- 7 y} cos (7 x) \cdot 7

\frac{d}{d x} (\frac{4 x}{5 2} + 3)

25 t^{2}

f (t) = 7 - \frac{1}{3} t

\int \frac{7 x ^{2} + 5 x + 7}{( x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (y^{3})

What is (\partial)/(\partial x)(e^{-7y}sin(7x)) ?
The answer to (\partial)/(\partial x)(e^{-7y}sin(7x)) is e^{-7y}cos(7x)*7