What is the integral from 1 to 6 of x^{-4} ?

The integral from 1 to 6 of x^{-4} is 215/648

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integral from 1 to 6 of x^{-4}

\int_{1}^{6} x^{- 4} d x

\frac{215}{648}

Decimal Notation

0.33179 \dots

Solution steps

\int_{1}^{6} x^{- 4} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{1}^{6}

= [- \frac{1}{3 x ^{3}}]_{1}^{6}

Compute the boundaries:

\frac{215}{648}

= \frac{215}{648}

\int \frac{3 x ^{3}}{49 - x ^{2}} d x

x^{2} - 3 x - 2

\frac{d}{d x} (arccos (\frac{x + 1}{3}))

y^{^{'}} = x + y, y (0) = 0

\int u^{2} d u

What is the integral from 1 to 6 of x^{-4} ?
The integral from 1 to 6 of x^{-4} is 215/648