What is implicit (dy)/(dx),y=e^{4x^2+1} ?

The answer to implicit (dy)/(dx),y=e^{4x^2+1} is (dy)/(dx)=e^{4x^2+1}*8x

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implicit (dy)/(dx),y=e^{4x^2+1}

implicit derivative

\frac{d y}{d x}, y = e^{4 x^{2} + 1}

\frac{d y}{d x} = e^{4 x^{2} + 1} \cdot 8 x

Solution steps

y = e^{4 x^{2} + 1}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = e^{4 x^{2} + 1} \cdot 8 x

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = e^{4 x^{2} + 1} \cdot 8 x

\frac{d y}{d x} = e^{4 x^{2} + 1} \cdot 8 x

\frac{\partial}{\partial y} (yz)

\frac{d}{d x} (x - 2 y)

\int \frac{x}{x + 1} d x

lo g_{10} (3 x)

\int \frac{1}{( 10 + x ) ^{2}} d x

What is implicit (dy)/(dx),y=e^{4x^2+1} ?
The answer to implicit (dy)/(dx),y=e^{4x^2+1} is (dy)/(dx)=e^{4x^2+1}*8x