What is the solution for y^'=0.05ln((2000)/y)y ?

The solution for y^'=0.05ln((2000)/y)y is y=(2000)/(e^{e^{\frac{-t-c_{1)}{20}}}}

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y^'=0.05ln((2000)/y)y

y^{^{'}} = 0.05 ln (\frac{2000}{y}) y

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

Solution steps

y^{'} (t) = 0.05 ln (\frac{2000}{y}) y

Solve separable ODE:

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

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What is the solution for y^'=0.05ln((2000)/y)y ?
The solution for y^'=0.05ln((2000)/y)y is y=(2000)/(e^{e^{\frac{-t-c_{1)}{20}}}}