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Popular >

y^'=(x^2)

Solution

y^{^{'}} = (x^{2})

Solution

y = \frac{x ^{3}}{3} + c_{1}

Solution steps

y^{'} (x) = (x^{2})

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} d x

\int x^{2} d x = \frac{x ^{3}}{3} + c_{1}

y = \frac{x ^{3}}{3} + c_{1}

Popular Examples

y^'=((5xsec(y/x)+y))/x

y^{^{'}} = \frac{( 5 x sec ( \frac{y}{x} ) + y )}{x}

derivative of y/(1-2x)

\frac{d}{d x} (\frac{y}{1 - 2 x})

integral of (e^x+1)/2

\int \frac{e ^{x} + 1}{2} d x

integral from a to b of 1/r

\int_{a}^{b} \frac{1}{r} d r

derivative of (-x^2-8)/((x^2-8)^2)derivative of

\frac{- x ^{2} - 8}{( x ^{2} - 8 ) ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x^2) ?
The solution for y^'=(x^2) is y=(x^3)/3+c_{1}