What is the solution for (-2xy^2+1y)dx+(-2x^2y+1x)dy=0 ?

The solution for (-2xy^2+1y)dx+(-2x^2y+1x)dy=0 is y=(c_{1})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-2xy^2+1y)dx+(-2x^2y+1x)dy=0

(- 2 x y^{2} + 1 y) d x + (- 2 x^{2} y + 1 x) d y = 0

y = \frac{c _{1}}{x}

Solution steps

(- 2 x y^{2} + 1 y) d x + (- 2 x^{2} y + 1 x) d y = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

(x^{2} + 9)^{- 3}

\frac{d}{d x} (x sec^{2} (π x))

x \to - 0 lim (2 x e^{2 x} + k x)

\int 1 + \frac{2}{t} d t

\int cot (17 x) d x

What is the solution for (-2xy^2+1y)dx+(-2x^2y+1x)dy=0 ?
The solution for (-2xy^2+1y)dx+(-2x^2y+1x)dy=0 is y=(c_{1})/x