What is (\partial)/(\partial y)(1-y^3) ?

The answer to (\partial)/(\partial y)(1-y^3) is -3y^2

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(\partial)/(\partial y)(1-y^3)

\frac{\partial}{\partial y} (1 - y^{3})

- 3 y^{2}

Solution steps

\frac{\partial}{\partial y} (1 - y^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) - \frac{\partial}{\partial y} (y^{3})

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (y^{3}) = 3 y^{2}

= 0 - 3 y^{2}

Simplify

= - 3 y^{2}

\frac{d y}{d x} = \frac{1 + x}{y}

x \to 0 lim (\frac{7}{x ^{2} + x} - \frac{7}{x})

\frac{\partial}{\partial x} (\frac{x y}{x + 1})

\frac{( s + 2 )}{( s + 1 ) ^{2}}

\frac{\partial}{\partial z} (x yz + x y^{5} + y z^{5} + z x^{5})

What is (\partial)/(\partial y)(1-y^3) ?
The answer to (\partial)/(\partial y)(1-y^3) is -3y^2