What is the derivative of (-3x+12/(2sqrt(6-x))) ?

The derivative of (-3x+12/(2sqrt(6-x))) is (3x-24)/(4(6-x)sqrt(6-x))

What is the first derivative of (-3x+12/(2sqrt(6-x))) ?

The first derivative of (-3x+12/(2sqrt(6-x))) is (3x-24)/(4(6-x)sqrt(6-x))

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\frac{d}{d x} (\frac{- 3 x + 12}{2 6 - x})

\frac{3 x - 24}{4 ( 6 - x ) 6 - x}

Solution steps

\frac{d}{d x} (\frac{- 3 x + 12}{2 6 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{- 3 x + 12}{6 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( - 3 x + 12 ) 6 - x - \frac{d}{d x} ( 6 - x ) ( - 3 x + 12 )}{( 6 - x ) ^{2}}

\frac{d}{d x} (- 3 x + 12) = - 3

\frac{d}{d x} (6 - x) = - \frac{1}{2 6 - x}

= \frac{1}{2} \cdot \frac{( - 3 ) 6 - x - ( - \frac{1}{2 6 - x} ) ( - 3 x + 12 )}{( 6 - x ) ^{2}}

Simplify

\frac{1}{2} \cdot \frac{( - 3 ) 6 - x - ( - \frac{1}{2 6 - x} ) ( - 3 x + 12 )}{( 6 - x ) ^{2}} : \frac{3 x - 24}{4 ( 6 - x ) 6 - x}

= \frac{3 x - 24}{4 ( 6 - x ) 6 - x}

\int \frac{I n ∣ x ∣}{x} d x

\frac{d}{d x} (\frac{1 - ln ( x )}{4 x ^{2}})

\int \frac{cos ( 5 x )}{1 + sin ^{2} ( 5 x )} d x

\frac{9}{s ( s + 1 ) ( s + 9 )}

\int \frac{x ^{2} - 1}{x ^{2} + 1} d x

What is the derivative of (-3x+12/(2sqrt(6-x))) ?
The derivative of (-3x+12/(2sqrt(6-x))) is (3x-24)/(4(6-x)sqrt(6-x))
What is the first derivative of (-3x+12/(2sqrt(6-x))) ?
The first derivative of (-3x+12/(2sqrt(6-x))) is (3x-24)/(4(6-x)sqrt(6-x))