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Popular >

4y^{''}+y=0

Solution

4 y^{^{''}} + y = 0

Solution

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

Solution steps

4 y^{''} (t) + y = 0

Solve linear ODE:

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

Popular Examples

sum from n=0 to infinity of n^2+n

n = 0 \sum \infty n^{2} + n

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f(s)=ln(ln(6s))

f (s) = ln (ln (6 s))

integral from 0 to 1 of x/(sqrt(x+1))

\int_{0}^{1} \frac{x}{x + 1} d x

derivative of f(x(x^2-x))

\frac{d}{d x} (f (x) (x^{2} - x))

Frequently Asked Questions (FAQ)

What is the solution for 4y^{''}+y=0 ?
The solution for 4y^{''}+y=0 is y=c_{1}cos(t/2)+c_{2}sin(t/2)