What is the sum from n=1 to infinity of-2/n ?

The sum from n=1 to infinity of-2/n is diverges

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sum from n=1 to infinity of-2/n

n = 1 \sum \infty - \frac{2}{n}

diverges

Solution steps

n = 1 \sum \infty - \frac{2}{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - 2 \cdot n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= - 2 diverges

= diverges

n = 1 \sum \infty \frac{1}{n} (\frac{x}{5})^{n}

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2 (ln (y)) y^{^{'}} - x^{9} y = 0

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\int (cos (3 x))^{2} d x

What is the sum from n=1 to infinity of-2/n ?
The sum from n=1 to infinity of-2/n is diverges