What is (\partial}{\partial x}(\frac{2x+y)/z) ?

The answer to (\partial}{\partial x}(\frac{2x+y)/z) is 2/z

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(\partial}{\partial x}(\frac{2x+y)/z)

\frac{\partial}{\partial x} (\frac{2 x + y}{z})

\frac{2}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{2 x + y}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (2 x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{z} (2 + 0)

Simplify

\frac{1}{z} (2 + 0) : \frac{2}{z}

= \frac{2}{z}

\int_{0}^{\frac{3 π}{2}} cos^{3} (29 x) d x

\frac{d}{d x} (\frac{x ^{3} + 3 x}{x ^{2} - 4 x + 3})

x \to \infty lim (- 2 e^{x})

\frac{d}{d x} ((2 - x) e^{x})

x \to 4 + lim (\frac{15}{x - 4})

What is (\partial}{\partial x}(\frac{2x+y)/z) ?
The answer to (\partial}{\partial x}(\frac{2x+y)/z) is 2/z