What is the derivative of sqrt(3x+4) ?

The derivative of sqrt(3x+4) is 3/(2sqrt(3x+4))

What is the first derivative of sqrt(3x+4) ?

The first derivative of sqrt(3x+4) is 3/(2sqrt(3x+4))

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derivative of

3 x + 4

\frac{3}{2 3 x + 4}

Solution steps

\frac{d}{d x} (3 x + 4)

Apply the chain rule:

\frac{1}{2 3 x + 4} \frac{d}{d x} (3 x + 4)

= \frac{1}{2 3 x + 4} \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= \frac{1}{2 3 x + 4} \cdot 3

Simplify

\frac{1}{2 3 x + 4} \cdot 3 : \frac{3}{2 3 x + 4}

= \frac{3}{2 3 x + 4}

n = 2 \sum \infty \frac{n}{2 ^{n}}

- u

\frac{d y}{d x} y = 3 x^{3} - 8 x^{2} + π

\int \frac{csc ^{2} ( x )}{cot ^{5} ( x )} d x

n = 1 \sum \infty \frac{1}{1 3 ^{n} - 5 ^{n}}

What is the derivative of sqrt(3x+4) ?
The derivative of sqrt(3x+4) is 3/(2sqrt(3x+4))
What is the first derivative of sqrt(3x+4) ?
The first derivative of sqrt(3x+4) is 3/(2sqrt(3x+4))