What is the first derivative of 3-t ?

The first derivative of 3-t is -1

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derivative of 3-t

derivative of

3 - t

- 1

Solution steps

\frac{d}{d t} (3 - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) - \frac{d t}{d t}

\frac{d}{d t} (3) = 0

\frac{d t}{d t} = 1

= 0 - 1

Simplify

= - 1

\int cos^{2} (π x) d x

\frac{2 - x e ^{x}}{x + e ^{x}}

2 y^{^{''}} + 27 y = 0, y (0) = 6, y^{^{'}} (0) = 5

\frac{d y}{d x} = (1 - y) cos (x)

\frac{d}{d x} (\frac{e ^{3 x}}{1 - x ^{2}})