What is the integral of x^{(-7)/3} ?

The integral of x^{(-7)/3} is -3/(4x^{4/3)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^{(-7)/3}

\int x^{\frac{- 7}{3}} d x

- \frac{3}{4 x ^{\frac{4}{3}}} + C

Solution steps

\int x^{\frac{- 7}{3}} d x

Apply the Power Rule

: - \frac{3}{4 x ^{\frac{4}{3}}}

= - \frac{3}{4 x ^{\frac{4}{3}}}

Add a constant to the solution

= - \frac{3}{4 x ^{\frac{4}{3}}} + C

\frac{d}{d x} (\frac{x ^{2} + x + 1}{x ^{2} + 3})

(15, 250), (25, 28)

\frac{d}{d x} ((2 - x + 3 x^{2}) (x^{3} + 5 e^{x}))

\int \frac{1}{2 - sin ^{2} ( x )} d x

(0) (4.2)

What is the integral of x^{(-7)/3} ?
The integral of x^{(-7)/3} is -3/(4x^{4/3)}+C