What is the integral from-1 to 0 of xe^x ?

The integral from-1 to 0 of xe^x is -1+2/e

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integral from-1 to 0 of xe^x

\int_{- 1}^{0} x e^{x} d x

- 1 + \frac{2}{e}

Decimal Notation

- 0.26424 \dots

Solution steps

\int_{- 1}^{0} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{- 1}^{0}

= [e^{x} x - \int e^{x} d x]_{- 1}^{0}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{- 1}^{0}

Compute the boundaries:

- 1 + \frac{2}{e}

= - 1 + \frac{2}{e}

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What is the integral from-1 to 0 of xe^x ?
The integral from-1 to 0 of xe^x is -1+2/e