What is (\partial)/(\partial x)(3cos(3x)) ?

The answer to (\partial)/(\partial x)(3cos(3x)) is -9sin(3x)

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(\partial)/(\partial x)(3cos(3x))

\frac{\partial}{\partial x} (3 cos (3 x))

- 9 sin (3 x)

Solution steps

\frac{\partial}{\partial x} (3 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= 3 (- sin (3 x) \cdot 3)

Simplify

= - 9 sin (3 x)

x \to 0 lim (\frac{2 x - x}{x})

\int \frac{x + 5}{x ^{2} + 5 x + 6} d x

y = x^{2} - 9, y = 8 x

e^{2 t} sin (j) (2 t)

\int e^{9 x + 1} d x

What is (\partial)/(\partial x)(3cos(3x)) ?
The answer to (\partial)/(\partial x)(3cos(3x)) is -9sin(3x)