What is the limit as x approaches-2 of 1/(|x+2|)+x^2 ?

The limit as x approaches-2 of 1/(|x+2|)+x^2 is infinity

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limit as x approaches-2 of 1/(|x+2|)+x^2

x \to - 2 lim (\frac{1}{∣ x + 2 ∣} + x^{2})

\infty

Solution steps

x \to - 2 lim (\frac{1}{∣ x + 2 ∣} + x^{2})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 2 - lim (\frac{1}{∣ x + 2 ∣} + x^{2}) = \infty

x \to - 2 + lim (\frac{1}{∣ x + 2 ∣} + x^{2}) = \infty

= \infty

y^{^{'}} = 2.5 - \frac{y}{2000}

\frac{d y}{d t} + \frac{1}{2} y = 17 sin (2 t), y (0) = - 1

\int x^{- 2} + x^{\frac{1}{5}} d x

\frac{d}{d x} (arctan (s x))

\frac{d}{d x} (tan (x - y))

What is the limit as x approaches-2 of 1/(|x+2|)+x^2 ?
The limit as x approaches-2 of 1/(|x+2|)+x^2 is infinity