What is laplacetransform 6(t-10) ?

The answer to laplacetransform 6(t-10) is 6/(s^2)-(60)/s

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laplacetransform 6(t-10)

laplace transform

6 (t - 10)

\frac{6}{s ^{2}} - \frac{60}{s}

Solution steps

L {6 (t - 10)}

Expand

6 (t - 10) : 6 t - 60

= L {6 t - 60}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 6 L {t} - L {60}

L {t} : \frac{1}{s ^{2}}

L {60} : \frac{60}{s}

= 6 \cdot \frac{1}{s ^{2}} - \frac{60}{s}

Refine

6 \frac{1}{s ^{2}} - \frac{60}{s} : \frac{6}{s ^{2}} - \frac{60}{s}

= \frac{6}{s ^{2}} - \frac{60}{s}

f (x) = \frac{11 x}{1 - x}

lo g_{4} (x^{2})

x \to \infty lim (7 + \frac{2}{x})

(- 6, 4), (- 11, - 1)

What is laplacetransform 6(t-10) ?
The answer to laplacetransform 6(t-10) is 6/(s^2)-(60)/s