What is the limit as n approaches-infinity of e^n ?

The limit as n approaches-infinity of e^n is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as n approaches-infinity of e^n

n \to - \infty lim (e^{n})

0

Solution steps

n \to - \infty lim (e^{n})

Apply the common limit:

n \to - \infty lim (e^{n}) = 0

= 0

n = 0 \sum \infty e^{2 n}

x \to 0 lim (\frac{6 ^{x} - 2 ^{x}}{x})

x \to 0 + lim (x^{3} ln (x))

f (x) = \frac{x}{x ^{2} + 9}

x (x + y) y^{^{'}} + y (3 x + y) = 0

What is the limit as n approaches-infinity of e^n ?
The limit as n approaches-infinity of e^n is 0