What is (\partial)/(\partial y)(x^2-x-12y+1) ?

The answer to (\partial)/(\partial y)(x^2-x-12y+1) is -12

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(\partial)/(\partial y)(x^2-x-12y+1)

\frac{\partial}{\partial y} (x^{2} - x - 12 y + 1)

- 12

Solution steps

\frac{\partial}{\partial y} (x^{2} - x - 12 y + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (12 y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (12 y) = 12

\frac{\partial}{\partial y} (1) = 0

= 0 - 0 - 12 + 0

Simplify

= - 12

\int_{0}^{27} \frac{4}{x ^{\frac{2}{3}}} d x

\int 5 x ln (4 x) d x

f (x) = x^{2} + 3 x - 7

\frac{\partial}{\partial s} (- 3 s^{2} + t^{2})

y^{^{'}} = y + 3

What is (\partial)/(\partial y)(x^2-x-12y+1) ?
The answer to (\partial)/(\partial y)(x^2-x-12y+1) is -12