What is the derivative of x^{(4/5}(x-4)^2) ?

The derivative of x^{(4/5}(x-4)^2) is (14x^2-72x+64)/(5x^{1/5)}

What is the first derivative of x^{(4/5}(x-4)^2) ?

The first derivative of x^{(4/5}(x-4)^2) is (14x^2-72x+64)/(5x^{1/5)}

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\frac{d}{d x} (x^{(\frac{4}{5})} (x - 4)^{2})

\frac{14 x ^{2} - 72 x + 64}{5 x ^{\frac{1}{5}}}

Solution steps

\frac{d}{d x} (x^{(\frac{4}{5})} (x - 4)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{\frac{4}{5}}, g = (x - 4)^{2}

= \frac{d}{d x} (x^{\frac{4}{5}}) (x - 4)^{2} + \frac{d}{d x} ((x - 4)^{2}) x^{\frac{4}{5}}

\frac{d}{d x} (x^{\frac{4}{5}}) = \frac{4}{5 x ^{\frac{1}{5}}}

\frac{d}{d x} ((x - 4)^{2}) = 2 (x - 4)

= \frac{4}{5 x ^{\frac{1}{5}}} (x - 4)^{2} + 2 (x - 4) x^{\frac{4}{5}}

Simplify

\frac{4}{5 x ^{\frac{1}{5}}} (x - 4)^{2} + 2 (x - 4) x^{\frac{4}{5}} : \frac{14 x ^{2} - 72 x + 64}{5 x ^{\frac{1}{5}}}

= \frac{14 x ^{2} - 72 x + 64}{5 x ^{\frac{1}{5}}}

\frac{d y}{d x} = \frac{x}{4 + x ^{2}}

\frac{d}{d x} (2^{x} ln (x))

\int \frac{x ^{2}}{x ^{3} + 1} d x

f (x) = e^{x^{2} + 1}

f (x) = 1 0^{x}

What is the derivative of x^{(4/5}(x-4)^2) ?
The derivative of x^{(4/5}(x-4)^2) is (14x^2-72x+64)/(5x^{1/5)}
What is the first derivative of x^{(4/5}(x-4)^2) ?
The first derivative of x^{(4/5}(x-4)^2) is (14x^2-72x+64)/(5x^{1/5)}