What is the derivative of t^3-12t ?

The derivative of t^3-12t is 3t^2-12

What is the first derivative of t^3-12t ?

The first derivative of t^3-12t is 3t^2-12

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derivative of

t^{3} - 12 t

3 t^{2} - 12

Solution steps

\frac{d}{d t} (t^{3} - 12 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (12 t)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (12 t) = 12

= 3 t^{2} - 12

y^{^{''}} = \frac{1}{x ^{2}} y

\int_{0}^{x} sin (t) d t

\int_{1}^{3} (x^{2} - 1) d x

\int_{1}^{100} \frac{1}{1 + x ^{2}} d x

4 x^{2}, 25

What is the derivative of t^3-12t ?
The derivative of t^3-12t is 3t^2-12
What is the first derivative of t^3-12t ?
The first derivative of t^3-12t is 3t^2-12